Using Find, Execdir, and Grep all in one command

Question

I'm trying to use a shell script to:

• return all .mov files in a given directory
• without path, file names only
• filtering out dot-underscore files from results
• separate each result by \n but haven't even gotten to that part

I don't know why there are dot underscore files, but it's a shared server so I didn't want to delete them just in case. There are also spaces in the Path, so separating results by spaces gives interesting results.

So far I've figured out how to do these things but not in tandem. This command will return all results, no dot underscore files, but it returns only the full path, can't get it to return basename:

results="$(find /Path/ -iname "*.mov" -type f | grep -vF '/._')"

And then this command will return only basenames, but includes dot-underscore files

results="$(find /Path/ -iname "*.mov" -execdir echo {} ';' | grep -vF '/._')"

As you can see in the second attempt I tried to link the two together... but somehow -execdir is making the command ignore the grep command at the end. I'm sure I'm just piping something wrong, but please let me know.

Answer 1

You can use find to skip unwanted files, no need to grepafterwards:

find PATH \( -name '._*' -prune \) -o -type f -iname '*.mov' -execdir echo {} \;

To create a text file with the result, add > path/to/text-file at the end.

PS: The reason your second command doesn't work is in the pattern used for grep. You strip out the path name in the find, so grep -v '^\._' should be used instead.