Ask Different is a question and answer site for power users of Apple hardware and software. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I'm making a column chart about certain dice rolls in the game Descent: Second Edition, and the problem I'm having is that there are multiple dice of the same color in the standard rolls. For example, you could roll a red die, or two red die. I would like to be able to color code the dice rolls, but with the fact that this can cause ambiguity, I would like to be abler to make checkered pattern, with line borders, so one can see if I'm talking about "red-red", "red", or "red-blue-yellow."

I would also like to be sure that when I apply this pattern that it repeats, so it doesn't end up stretched or squashed depending on the columns height. If it came down to it, I could devise a "pin stripe" design to make that moot, but, that's the thing, I don't know my options.

Here's what I have now. Notice the ambiguity and confusion in the colors.

Current Color Scheme

Here's what I would like to be able to do. Just by looking at it, you can tell what's being referred to.

Wanted Color Scheme

share|improve this question
Your goal is somewhat unclear. A better description of what you're trying to accomplish--perhaps even a "cocktail napkin sketch"--would help the community to provide a solution. – jaberg Jan 24 '13 at 19:20
up vote 1 down vote accepted

You can use the Graphic Inspector to set a gradient fill for any object, including a cell, in Numbers. This might work for the two-color combinations.

However, the best way to accomplish this would be to create an image file for each of the combinations and use the necessary file to fill the cell. The image can be scaled to fit within a single cell.

screenshot: accessing the graphics inspector in Numbers

Screenshot: Selecting a fill style within the Graphics Inspector

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.